How (and why) to Ramble on your goat sideways
01-27-2012, 10:00 AM
Tour de Franzia
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You have probrem? It was the right price. The fronts have 1/2" grooves.
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01-27-2012, 10:14 AM
Tour de Franzia
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I should probably note that the rear shocks appear to be too short and I can't get the car higher than 4" so I have to come up with something, the spring is seated on the upper and lower perches at full droop.
BTW, full droop wheel position in the fender well is "lower" than factory Miata ride height, lol.
BTW, full droop wheel position in the fender well is "lower" than factory Miata ride height, lol.
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01-27-2012, 11:09 AM
So at work we have the "UPS Computer" which is really just an aging Dell desktop that UPS supplied when we set up our shipper account. [...] Today I decided to take on the project of preparing a few basic upgrades and then wiping the hard drive and reinstalling Windows XP.
I did find my old Matrox Millenium II PCI video card, however. Who knows why I kept that and tossed the AGP card.
So, now the computer has...
Celeron 2.4 GHz
768 MB DDR SDRAM @ 333 MHz
Onboard Intel vidchip
...and it's not terrible with a clean install of XP.
Yay.
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01-27-2012, 12:42 PM
2 Props,3 Dildos,& 1 Cat
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remember back in school when you learned the equation of a line?
y=m*x+b ?
it's a first order polynomial. x is raised to the 1 power. the graph of the equation is a straight line. linear.
That means that for whatever input you stick in for x, you'll get a value of y that is "m times" more than x.
or in the case of springs, for every inch you compress, you get "k times" (since the spring equation is F=k*x) that amount of force in pounds (assuming your rate "k" is in lbs/inch).
and for most springs with equal spacing between coils (which your ASTs appear to have) they are constant rate. or "linear springs". That means that no matter what length they are at, the spring rate never changes. so if they are unloaded and sitting on a desk, they are still the same rate as they are just before they are coil binding. at coil bind, the spring rate is effectively the spring rate of solid steel. or rounding up: infinite.
References:
http://en.wikipedia.org/wiki/Degree_of_a_polynomial
y=m*x+b ?
it's a first order polynomial. x is raised to the 1 power. the graph of the equation is a straight line. linear.
That means that for whatever input you stick in for x, you'll get a value of y that is "m times" more than x.
or in the case of springs, for every inch you compress, you get "k times" (since the spring equation is F=k*x) that amount of force in pounds (assuming your rate "k" is in lbs/inch).
and for most springs with equal spacing between coils (which your ASTs appear to have) they are constant rate. or "linear springs". That means that no matter what length they are at, the spring rate never changes. so if they are unloaded and sitting on a desk, they are still the same rate as they are just before they are coil binding. at coil bind, the spring rate is effectively the spring rate of solid steel. or rounding up: infinite.
References:
http://en.wikipedia.org/wiki/Degree_of_a_polynomial
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01-27-2012, 12:48 PM
I identify as a bear.
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In this context, linearity describes the condition where the response produced by a system is always proportional to the input into the system, regardless of the magnitude of the input.
One example would be that applying 500 lbs of force to a spring causes it to compress by 1", applying 1,000 lbs causes it to compress by 2", applying 1,500 lbs for force causes it to compress by 3", etc. For every additional 500 lbs you add, the spring will compress by another inch.
In other words, the spring's effective rate does not change simply because it already partially compressed. It responds the same way (by compressing 1" per 500 lbs) regardless of how much input (weight) has already been applied to it, in much the same way that your mom's response to "input" does not vary throughout the course of the evening regardless of how much "input" she has already had.
edit: y8s beat me to it. And I got a chuckle out of "rounding up to infinity."
One example would be that applying 500 lbs of force to a spring causes it to compress by 1", applying 1,000 lbs causes it to compress by 2", applying 1,500 lbs for force causes it to compress by 3", etc. For every additional 500 lbs you add, the spring will compress by another inch.
In other words, the spring's effective rate does not change simply because it already partially compressed. It responds the same way (by compressing 1" per 500 lbs) regardless of how much input (weight) has already been applied to it, in much the same way that your mom's response to "input" does not vary throughout the course of the evening regardless of how much "input" she has already had.
edit: y8s beat me to it. And I got a chuckle out of "rounding up to infinity."
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