Painting intercooler black - good or not?
#25
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I like the bling
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I need Newbsauce's hood pins.
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I need Newbsauce's hood pins.
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#31
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Carbontrix
Mini Cooper
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#34
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h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
#36
2 Props,3 Dildos,& 1 Cat
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Join Date: Jun 2005
Location: Fake Virginia
Posts: 19,338
Total Cats: 573
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Assuming:
h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
emissivity of flat blackness = hi fi
add that to your calcs and smoke it
#37
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Assuming:
h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
#40
Tour de Franzia
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iTrader: (6)
Join Date: Jun 2006
Location: Republic of Dallas
Posts: 29,085
Total Cats: 375
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Assuming:
h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
h_air = 50 W/m*k
h_aluminum = 221 W/m*k
h_polyethylene = 0.50 W/m*k (closest thing to paint I can find...)
I found some formula and got a heat transfer coefficient of:
without paint: 40.774155458486 W/m*k
with paint: 40.774153752544 W/m*k
For a reduction in heat transfer of 0.0000042%. Not a whole lot. Not 100% sure I did it right though. I'm going over it.
[/classic chris rock]